A student dissolves 15.g of sucrose C12H22O11 in 300.mL of a solvent with a density of 1.13/gmL. The student notices that the volume of the solvent does not change when the sucrose dissolves in it. Calculate the molarity and molality of the student's solution. Be sure each of your answer entries has the correct number of significant digits

The molarity and molality of sucrose solution is 0.146 M and 0.129 m respectively

Explanation:

To calculate the molarity of solution, we use the equation:

Given mass of sucrose = 15 g

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 300 L

Putting values in above equation, we get:

Hence, the molarity of sucrose solution is 0.146 M

To calculate the mass of solvent, we use the equation:

Density of solvent = 1.13 g/mL

Volume of solvent = 300 mL

Putting values in above equation, we get:

To calculate the molality of solution, we use the equation:

where,

= Given mass of solute (sucrose) = 15 g

= Molar mass of solute (sucrose) = 342.3 g/mol

= Mass of solvent = 339 g

Putting values in above equation, we get:

Hence, the molality of sucrose solution is 0.129 m

3 1/4 %

explanation:

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