1. What is the mass of 25.0 L of neon at STP?

m= 22.2 g Ne

Explanation: First find the moles of Ne using Ideal Gas Law and derive for n. So from PV= nRT the mole is derived as n = PV /RT

n = PV / RT

= 1 atm ( 25 L ) / 0.0821 L.atm /

mole.K ( 273 K )

= 1.11 moles Ne

Convert it to mass using the molar mass of Neon

1.11 moles Ne x 20 g Ne / 1 mole Ne

= 22.2 g Ne

1 a

2 d

3 a

4 c

explanation: