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2SO3(g) -> 2SO2(g)+O2(g)
Calculate Keq for this reaction if the equalibrium concentrations are: |SO2|=0.42M; |O2|=0.21M; |SO3|=0.072M

The equilibrium constant for the reaction comes out to be 7.145

Explanation:

Given concentration of all the species at equilibrium are shown below

\\

Given reaction is shown below

for the reaction is 7.145

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

answer: they produce more slow than unicellular organisms.