A 2.00 L container of nitrogen has a pressure of 3.2 atm. What volume would the container be at if the pressure decreased to 1.00 atm

The volume would be 6,4 L

Explanation:

We use the Boyle Mariotte formula, according to which for a certain mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1 = P2xV2

V2= (P1xV1)/P2= (3,2 atm x 2, 00 L)/1,00 atm= 6,4 L

answer: h+ its less than oh

explanation:

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%