A solution contains 2.0 ⨯ 10−4 M Ag+(aq) and 1.5 ⨯ 10−3 M Pb2+(aq). If NaI is added, will AgI (Ksp = 8.3 ⨯ 10−17) or PbI2 (Ksp = 7.9 ⨯ 10−9) precipitate first? Specify the concentration of I−(aq) needed to begin precipitation.

The silver iodide will precipitate first.

At concentration more than of iodide ion will result in precipitation of silver iodide.

At concentration more than of iodide ion will result in precipitation of lead iodide.

Explanation:

Solubility of silver iodide =

Concentration of silver ions =

Suppose concentration of iodide ion due NaI added in solution be =

The expression of solubility product will be given as :

At concentration more than of iodide ion will result in precipitation of silver iodide.

Solubility of lead iodide =

Concentration of silver ions =

Suppose concentration of iodide ion due NaI added in solution be =

The expression of solubility product will be given as :

At concentration more than of iodide ion will result in precipitation of lead iodide.

For silver iodide , we need concentration of iodide more than and for lead iodide , we need concentration of iodide more than 0.0023 M. So , this indicates that silver iodide will precipitate out first.

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

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in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.