The pressure on 2.50L of N20 changes from 105 kPa to 40.5 kPa. if the temperature does not change, what will the new volume be.

6.48L

Explanation:

Given parameters:

V₁ = 2.5L

P₁  = 105 kPa

P₂  =  40.5 kPa

Condition: constant temperature

Unknown:

V₂  = ?

Solution:

To solve this problem, we are considering pressure and volume relationship. This should be solved by applying the knowledge of Boyle's law.

The law states that "The volume of fixed mass of a gas varies inversely as the pressure changes if the temperature is constant".

Mathematically;

                     P₁V₁  = P₂V₂

where P and V are pressure and volume, 1 and 2 represents initial and final states.

Substitute to find the V₂;

                  105 x 2.5  = 40.5 x  V₂

        Solving for V₂ gives 6.48L

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