What is the percent composition of each of the elements in Al(OH) 3 ?

%Al = 34.6%

%0 = 61.5%

%H = 3.9%

Explanation:

Al(OH)3

Atomic mass of Aluminum Al = 27

Atomic mass of Oxygen O=16

Atomic mass of Hydrogen H=1

Molar mass of Al(OH)3 = 27 + (16*3) + (1*3)

Al(OH)3 = 27 + 48 + 3

Al(OH)3 = 78

Percentage composition;

Aluminum Al= (27/78) × 100

Aluminum Al=0.346 × 100 =34.6%

Oxygen O=(16*3/78) × 100

Oxygen O= 0.615 × 100 =61.5%

Hydrogen H= (1*3/78) × 100

Hydrogen H=0.039 × 100=3.9%