20ml of 2M KOH are placed into a beaker. 4M CH 3 COOH are placed into a burette.

a. Predict what volume of CH 3 COOH will be needed to neutralize the KOH.

Volume of CH3COOH will be needed to neutralize the KOH is 10 ml.

Explanation:

In the titration process the concentration of unknown analyte be it acid or base is calculated by the formula:

Macid x Vacid = Mbase x Vbase       equation 1

Data given:

volume of base KOH = 20 ml

molarity of base = 2M

Molarity of CH3COOH acid = 4 M

Volume  of CH3COOH acid = ?

Putting the values in the equation  1

4 x V acid = 20 x 2

V acid =

V acid = 10 ml

The neutralization of KOH by CH3COOH will be done by using 10 ml of 4M solution of CH3COOH against 20 ml of 2M KOH.

just did the assignment and the answer was #1 +2 n

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.