How many grams of C are required to react with 32.1 g of Fe2O3?

3.62 g of C are required

Explanation:

In order to determine the grams of C, in the reaction we have to define it:

Reactants are C and Fe₂O₃

The reaction is:

3C(s) + 2Fe₂O₃(g) → 4Fe(s) + 3CO₂(g)             It is a redox reaction.

We convert the mass of the oxide to moles:

32.1 g . 1 mol/ 159.7g = 0.201 moles

In the reactant side we say:

2 moles of oxide need 3 moles of C to react

Therefore 0.201 moles of oxide must need (0.201 . 3) / 2 = 0.3015 moles of C

We convert the moles to mass → 0.3015 mol . 12 g / 1 mol = 3.62 g

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2