How many moles of HNO3 are present if 4.90×10−2 mol of Ba(OH)2 was needed to neutralize the acid solution?

0.098 moles of HNO₃ are present if 4.90× mol of Ba(OH)₂ was needed to neutralize the acid solution

Explanation:

1 mole of Ba(OH)₂ contains 2 moles of OH- ions.

Hence, 0.049 moles of Ba(OH)2 contains x moles of OH- ions.

cross multiplying, we have

1 mole * x mole = 2 moles * 0.049 mole

x mole = 2 * 0.049 / 1

x mole =  0.098 moles of OH- ions.

1 mole of OH- can neutralize 1 mole of H+

Therefore, 0.098 moles of HNO₃ are present if 0.049 moles of Ba(OH)₂ was needed to neutralize the acid solution.

може ли да зареждате повече информация, моля

the correct answer would be b. amelia, because the particals of gas move really fast (charged particals) and gas also has a lot of room (particals move independently) so the only answer that has both of those is amelia's.