Determine the volume of SO2 (at STP) formed from the reaction of 96.7 g of FeS2 and 55.0 L of O2 (at 398 K and 1.20 atm). The molar mass of FeS2 is 119.99 g/mol. 4 FeS2(s) + 11 O2(g) → 2 Fe2O3(s) + 8 SO2(g)

The volume of SO₂ formed from the reaction at STP is 32.92 L

From the question,

We are to determine the volume of SO₂ formed from the reaction

The given balanced chemical equation for the reaction is

4FeS₂(s) + 11O₂(g) → 2Fe₂O₃(s) + 8SO₂(g)

This means,

4 moles of FeS₂ reacts with 11 moles of oxygen to produce 2 moles of Fe₂O₃ and 8 moles of SO₂

First, we will determine the number of moles of each reactant present

Mass = 96.7 g

From the formula

Molar mass of FeS₂ = 119.99 g/mol

∴ Number of moles of FeS₂ present =

Number of moles of FeS₂ present = 0.8059 mole

Using the formula

PV = nRT

Putting the given parameters into the formula, we get

n = 2.0208 moles

Since,

4 moles of FeS₂ reacts with 11 moles of oxygen to produce 8 moles of SO₂

Then,

moles of FeS₂ will react with 2.0208 moles of oxygen to produce  moles of SO₂

That is,

0.7348 moles of FeS₂ will react with 2.0208 moles of oxygen to produce 1.4697 moles of SO₂

∴ Number of moles of SO₂ formed is 1.4697 moles

Now for the volume of SO₂ formed at STP

Since

1 mole of a gas has a volume of 22.4 L at STP

Then

1.4697 moles of the SO₂ will have a volume of 1.4697 × 22.4 L

1.4697 × 22.4 L = 32.92L

Hence, the volume of SO₂ formed from the reaction at STP is 32.92 L

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 32.9 Liters

Explanation:

To calculate the moles, we use the equation:

1. moles of

2. moles of

P = pressure of the gas = 1.20  atm

R = Gas constant =

T = temperature of the gas =

According to stoichiometry:

11 moles of oxygen reacts with 4 moles of

Thus 2.02 moles of oxygen reacts with = moles of

Thus oxygen acts as limiting reagent and is excess reagent.

As 11 moles of oxygen gives = 8 moles of

2.02 moles of oxygen gives = moles of

P = pressure of the gas = 1  atm (at STP)

R = Gas constant =

T = temperature of the gas =   (at STP)

Thus volume of (at STP) formed from the reaction is 32.9 L

1 is the answer to this problem