Calculate the molarity of a solution with 233.772g sodium chloride dissolved in 2,000mL of water

The molarity is 2M

Explanation:

First , we calculate the weight of 1 mol of NaCl:

Weight 1mol NaCl= Weight Na + Weight Cl= 23 g+ 35, 5 g= 58, 5 g/mol

58,5 g---1 mol NaCl

233,772 gx= (233,772 g x1 mol NaCl)/58,5 g= 4 mol NaCl

A solution molar--> moles of solute in 1 L of solution:

2 L4 mol NaCl

1Lx0( 1L x4mol NaCl)/4L =2moles NaCl---> 2 M

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