A 100.0g sample of tin is heated to 100.0 oC (Celsius) and is placed in a coffee cup calorimeter containing 150. g of water at 25.0 oC. After the metal cools, the final temperature of the metal and the water is 27.4 oC. Calculate the specific heat capacity of tin from these experimental data, assuming that no heat escapes to the surroundings or is transferred to the calorimeter. Specific heat of water

Explanation:

It is known that specific heat of water is 4.184 and atomic mass of tin is 118.7 g/mol. For the given situation,

Let us assume that,

                = mass of Sn

                = mass of  

Therefore, heat energy expression for heat lost and gained is as follows.

                              = 0.207

For, 118.7 g the specific heat of tin will be calculated as follows.

                          = 24.5

Thus, we can conclude that specific heat of tin is 24.5 .