At 25 oC the solubility of copper(I) chloride is 1.00 x 10-3 mol/L. Calculate the value of Ksp at this temperature. Give your answer in scientific notation to 2 SIGNIFICANT FIGURES (even though this is strictly incorrect).

4.0 × 10⁻⁹

Explanation:

Let's consider the solution of copper(I) chloride.

CuCl₂(s) ⇄ Cu²⁺(aq) + 2 Cl⁻(aq)

We can relate the solubility (S) with the solubility product constant (Ksp) using an ICE chart.

        CuCl₂(s) ⇄ Cu²⁺(aq) + 2 Cl⁻(aq)

I                             0                 0

C                           +S              +2S

E                             S                2S

The Ksp is:

Ksp = [Cu²⁺] × [Cl⁻]² = S × (2S)² = 4 S³

Ksp = 4 × (1.00 × 10⁻³)³ ≈ 4.0 × 10⁻⁹

a is the answer to this question

explanation: