How many grams of LiCl are in 1 L of a 0.05 M LiCl solution

The answer is 2, 12 g of LiCl in 1 L of solution

Explanation:

We calculate the weight of 1 mol of LiCl:

Weight 1 mol LiCl= Weight Li + Weight Cl =6, 94 g + 35, 45 g= 42,39 g/mol

In a 0.05M solution it means that we have 0.05 moles of compound (in this case, LiCl) in 1 liter of solution:

1 mol42, 39 g LiCl

0,05molx=(0,05molx 42, 39 g LiCl)/ 1 mol =2, 1195 g LiCl

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