A carbon forms two bonds to two X atoms plus two more bonds to two hydrogen atoms. If the hybridization to each X has 79.7% p-character, what is the X-C-X bond angle in degrees to the nearest tenth of a degree? Hint: recall our discussion of Bent's rule and Coulson's directionality theorem.

The bond angle is equal to 104.8°

Explanation:

With the Bent's rule, smaller bonds are formed between the ligands of the electronegative element, therefore, we have to:

cosθ = (p-1)/p, where p = 79.7% = 0.797

Replacing:

cosθ = (0.797-1)/0.797

θ = cos^-1(-0.254) = 104.8°

sorry idk the answer well to you i have a explaination

explanation: a formula which shows the arrangement of atoms in the molecule of a compound

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.