2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the equilibrium temperature is 10.93ºC. Show your work!

a. Calculate the total heat (in J) lost by the water (specific heat for water is 4.184 J/g°C).

b. Calculate the heat gained by the ice cube after it melts (specific heat for ice is 2.093 J/g°C).

c. Calculate the heat it took to melt the ice. (It takes 334.0 J/g of heat energy to melt ice). qmelt = mice ΔHmelt

The heat lost  by the water   3.8 KJ

The heat gain by ice   = 228.76 J

The heat required to melt the ice = 3340 J

Explanation:

Mass of ice cube = 10 gm

Initial temperature of ice cube = 0 °c

Mass of water = 100 gm

Initial temperature of water = 20 °c

Final temperature of mixture = 10.93 °c

(a). Total heat lost by the water   ( - )

⇒ 100 × 4.184 (20 - 10.93)

⇒ 3.8 KJ

This is the heat lost  by the water.

(b). Heat gained by the ice cube =

⇒ = 10 × 2.093 × ( 10.93 - 0)

⇒ = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice = × Latent Heat

⇒ = 10 × 334

⇒ = 3340 J

This is the heat required to melt the ice.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: