Need Help check my answer
How many grams of KNO3 will be produced if 150 grams of KI are allowed to react completely with lead nitrate
Use. 2KI + Pb(NO3)2 arrow 2 KNO3+PbI2
I got 91.4 g KNO3

91.27g

Explanation:

2KI + Pb(NO3)2 —> 2KNO3 + PbI2

Molar Mass of KI = 39 + 127 = 166g/mol

Mass of KI from the balanced equation = 2 x 166 = 332g

Molar Mass of KNO3 = 39 + 14 + (16x3) = 39 + 14 + 48 = 101g/mol

Mass of KNO3 from the balanced equation = 2 x 101 = 202g

Now we can obtain the mass of KNO3 produced as follows:

From the equation:

332g of KI produced 202g of KNO3.

Therefore, 150g of KI will produce = (150x202)/332 = 91.27g of KNO3

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.