For the question(s) that follow, consider the following equation. Mg3N2(s) + 6H2O(l) → 3Mg (OH)2(s) + 2NH3(g) What is the correct form of the conversion factor needed to convert the number of moles of H2O to the number of moles of NH3 produced?

2/6

Explanation:

In a balanced chemical equation as:

aA + bB → cC + dD

Where coefficients of reaction relates the number of moles of substances that are involved in the reaction. In the reaction:

Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)

Per mole of Mg₃N₂(s) and per 6 moles of H₂O you will produce 3 moles of Mg(OH)₂(s) and 2 moles of NH₃(g).

To convert moles of H₂O to moles of NH₃ you can use:

X moles of H₂O ₓ (2 moles NH₃ / 6 moles of H₂O)

That means conversion factor to convert the number of moles of water to number of moles of ammonia is 2/6.

-It is important to say that obtention of conversion factor requires, in the first, the balanced chemical equation-

I hope it helps!