Consider the reaction 2 A(g) ⇄ B(g) + C(g) K = 0.035 A mixture of 8.00 moles of B and 12.00 moles of C in a 20.0 L container is allowed to reach equilibrium. What is the equilibrium concentration of A?

52.37 moles.

Explanation:

The value of reaction quotient of a reaction when it has reached to the equilibrium is known as Chemical Equilibrium.

The equation of chemical equilibrium for the reaction mentioned in the question will be as follows -

 Where, the entities in the large bracket denote the concentrations of respective species in the reaction.

Thus following this equation, the equilibrium concentration of reactant A will be -

moles.

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6.4 cm (max) - 25 cm (min)