A sealed container holding 0.0255 L 0.0255 L of an ideal gas at 0.979 atm 0.979 atm and 65 ∘ C 65 ∘C is placed into a refrigerator and cooled to 37 ∘ C 37 ∘C with no change in volume. Calculate the final pressure of the gas.

0.897 atm

Explanation:

In order to determine the final pressure of the gas, we use the Ideal Gases Law for both situations:

Initial situation is → P₁ . V₁ = n . R . T₁

Second situation is P₂ . V₂ = n . R . T₂

P₁ / T₁ = P₂ / T₂ as R is a constant, and the n and V stay the same

We convert the temperature to absolute values:

65°C +273 = 338 K

37°C + 273 = 310 K

0.979 atm / 338 K = P₂ / 310K

(0.979 atm / 338 K)  . 310K = P₂ → 0.897 atm

As temperature decreased, the pressure decreased too when the volume of the gas remains constant.

the answer for sodium is 0.186

the answer for rubidium is 0.251

geosphere and hydrosphere.

this is because the geosphere has to do with geological events, while the hydrosphere controls all water on earth.