For Questions 1 through 4 - Consider a solution prepared by combining 45.0 g of BaCl2 with enough water to prepare a 750.0 mL of solution. Assume that the volume of water added was 748 mL. Density of water is 1.00 g/mL. Answer questions 1 through 4. 1) What is the molarity of BaCl2 in the solution?

The molality of barium chloride solution is 0.289 m

Explanation:

To calculate the mass of water, we use the equation:

Density of water = 1 g/mL

Volume of water = 748 mL

Putting values in above equation, we get:

To calculate the molality of solution, we use the equation:

where,

= Given mass of solute (barium chloride) = 45.0 g

= Molar mass of solute (barium chloride) = 208.23  g/mol

= Mass of solvent (water) = 748 g

Putting values in above equation, we get:

Hence, the molality of barium chloride solution is 0.289 m

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.