An ion Mn+ has a single electron. The highest energy line in its emission spectrum occurs at a frequency of 8.225 × 1016 Hz. Identify the ion. (Enter the symbol of the element in the first box, and its charge in the second.)

Answer :  The element is boron and ion is

Explanation :

Using Rydberg's Equation:

Where,

= change in energy

Z = atomic number

= Higher energy level =

= Lower energy level = 1

Putting the values, in above equation, we get

             ............(1)

As we know that:

   .......(2)

Now equation 1 and 2, we get:

Z = 4.99 ≈ 5

The element is boron that has atomic number 5.

As it has only one electron the charge on the B is (+4) that is,

Thus, the element is boron and ion is

b is the correct answer

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