8. Imagine water flowing in a stream with a diameter of 1.5m at a speed of 6.8 m/s. If a rock blocked half of the
stream, how fast would the water flow around the rock? Use A V = A, V, equation. Area of a circle = 1. Do work
on a separate sheet of paper.
m/s
9. If the stream (back to its 1.5m diameter and 6.8 m/s speed) flowed downhill 18 meters, how fast would we expect
it to flow?
HELPPP ??? I HAVE A TEST RN

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

idk i'm not smart

explanation:

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