What is the molarity of 5 g of NaOH in 750 mL of solution?
THERE ARE
Pl

0.167M

Explanation:

First, let us calculate the number of mole of NaOH present in 5g. This is illustrated below:

Molar Mass of NaOH = 23 + 16 + 1 = 40g/mol

Mass of NaOH from the question = 5g

Number of mole = Mass /Molar Mass

Number of mole of NaOH = 5/40

Number of mole of NaOH = 0.125mol

Now, we can easily find the molarity of the solution as follows:

Mole = O.125mole

Volume = 750 mL = 750/1000 = 0.75L

Molarity =?

Molarity = mole /Volume

Molarity = O.125mole/0.75L

Molarity = 0.167M

Therefore, the molarity of the solution is 0.167M

2b2t

explanation:

2b2t