Below is a metabolic pathway having 3 chemical reactions and 3 enzymes. Enzyme 1 has 2 binding sites--1 for the substrate A and another for the end product D. As the pathway proceeds, the end product in higher quantities will react with enzyme 1, blocking the enzyme's binding to the substrate. Which statement is true about this pathway

The statements are not available therefore the basis of assumption this question can be answered.

This is the non-competitive inhibition.

Explanation:

Non-competitive inhibition is the enzyme-catalyzed reaction in which a substrate binds to a site of the enzyme other than the active site. The binding of the substrate to the enzyme changes the conformation of the enzyme that is the active site also as a result of which the substrate not able to bind the active site properly and the product formation is reduced.

In the given question, since the same scenario has been observed therefore this is the case of non-competitive inhibition.

Thus, non-competitive inhibition is correct

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be

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