The dissociation of calcium carbonate has an equilibrium constant of at 800. °C. a What is for the reaction? = Correct Recall that and are related by the equation: The equation: has . Note that . Applying the relationship: b If you place 28.5 g of in a 9.77-L container at 800. °C, what is the pressure of in the container? Pressure = atm Correct For the dissociation of calcium carbonate: c What percentage of the original 28.5-g sample of remains undecomposed at equilibrium? Percentage = %

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

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