Identify the types of intermolecular forces found for each of the liquids and relate these to the shape of the drop as seen from the side. Include the terms cohesive and adhesive forces properly in your explanations.
What forces (dipole-dipole, hydrogen bonds, or dispersion forces) are present in each sample?
a) C12H26 (oil)
b) H2O (water)

Explanation:

Oil molecules are non-polar, and they can't form hydrogen bonds. Dispersion forces are present in C12H26 (oil).

H20 (water) are polar, has hydrogen bonds, it also has dipole-induced dipole and London dispersion forces.

The difference between them is that adhesion refers to the clinging of unlike molecules and cohesion refers to the clinging of like molecules.

In C12H26 (oil)  the adhesive forces are stronger than the cohesive forces as a result, oil molecules tend to stick to the walls of the container.

In  H2O (water) the cohesive forces is greater than the adhesive forces, as a result water molecules tend to stick together.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml