How many g of zinc are required to produced 50g of hydrogen when reacting zinc with sulphuric acid?

1621.53 g Zn.

Explanation:

The balanced equation is:

Zn + H2SO4  --->  ZnSO4 + H2.

So, using the molar masses of Zn and H2:

65.38 g of Zn produces 2*1.008 = 2.016 g H2.

Thus 2.016 g of H2 is produced from 65.38 g Zn.

and 50g H2 is produced from   (50 * 65.38) / 2.016 g

= 1621.53 g Zn.

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