A sample of argon has a volume of 5.0 dm^3 and the pressure is 0.92 atm.
If the final temperature is 30.° C, the final volume is 5.7 L, and the final
pressure is 800. mm Hg, what was the initial temperature of the argon?

232.9K

Explanation:

V₁  = 5dm³

P₁  = 0.92atm

T₂ = 30°C

V₂ = 5.7L

P₂ = 800mmHg

Unknown:

T₁ = ?

Solution:

To solve this problem, we are going to apply the combined gas law which is fusion of the avogadro's law, boyle's law and charles's law.

 Mathematically;

p, v and T are pressure, volume and temperature respetively

1 and 2 depicts the initial and final states.

We need to convert ;

     temperature to K and pressure into atm

T₂  = 30°C  = 273 + 30 = 303K

P₂  =  800mmHg;

         760mmHg  = 1 atm

           800mmHg  =  = 1.05atm

   Input the variables and solve;

    T  = 232.9K

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

a