The pressure of a gas at 10 degrees celsius is greater that the pressure of the gas at 30 degrees celsius
True
False

False

Explanation:

According to Gay-Lussac Law,

"The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles"

Mathematical relationship:

P₁/T₁ = P₂/T₂

P₁ = Initial pressure

T₁ = Initial temperature

P₂ = Final pressure

T₂  = Final temperature

Now consider that at temperature of 10°C pressure was 6 atm. When temperature is increases to 30°C the pressure will be,

Initial temperature = 10 + 273 = 283 K

Final temperature = 30 + 273 = 303 K

Initial pressure = 6 atm

Final pressure = ?

Now we will put the values in formula:

6 atm / 283 K = P₂/303 K

P₂ = 6 atm × 303 K / 283 K

P₂ = 1818 atm. K /283 K

P₂ = 6.4 atm

So pressure will increase by increasing the temperature.

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