What is the complete ionic equation of Al2(SO4)3(aq) + 2K3PO4 (aq) = 2AlPO4 (s) + 3K2SO4 (aq)?

Explanation:

1. First, you want to break up the aqueous solutions into their respective ions (remember to write the charge and number of each element). Note that you can only do this to compounds marked as aqueous, so leave the solid be.

(Technically, both Potassium ions would have a coefficient of 6. I am leaving them as they were originally just for ease)

2. Now, you want to get rid of compounds on each side that are the same. These are called spectator ions, and they are exactly as the name says: they simply "spectate" the reaction, meaning they can be removed from the complete ionic equation.

Both the sulfate and potassium ions would be considered spectator ions and would be canceled out. Once removed the equation would look like:

3. The complete ionic equation would be:

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.