1. The total translational kinetic energy of the molecules of a sample of gas at
437 K is 32300 J. How many moles does the sample comprise?

moles of the sample:mol

2. Find the average translational kinetic energy of a single molecule.

average translational kinetic energy:J

1. KE = nRT

    32300 J = (n)××437K

    32300 J  =

                n =

                n =

2. KE =  KT

Explanation:

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