How many moles of O2 are needed to react with 8.95 moles of Al?

6.71 moles of O₂

Explanation:

When the reactans are oxygen and aluminum, you produce aluminum oxide by this reaction:

4 Al + 3O₂  →  2Al₂O₃

The stoichiometry indicates that 4 moles of Al reacts with 3 moles of O₂.

Let's make a rule of three:

If 4 moles of Al reacts with 3 moles of O₂

Then, 8.95 moles of Al will react with (8.95 . 3) / 4 = 6.71 moles

We need 6.71 moles of O2 to react with 8.95 moles of Al

Explanation:

Step 1: Data given

Number of moles of Al = 8.95 moles

Step 2: The balanced equation

4Al + 3O2 → 2Al2O3

Step 3: Calculate moles number of moles O2 needed to react with Al

For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3

For 8.95 moles Al we need 3/4 * 8.95 = 6.71 moles O2

There will 8.95/2 = 4.48 moles Al2O3 be produced

We need 6.71 moles of O2 to react with 8.95 moles of Al