What is deltaG at 298 K for the reaction
C + O2 = CO

The answer for the following problem is mentioned below.

Therefore the Gibbs free energy (ΔG) for the reaction is -394.36 J

Explanation:

Given:

ΔH = -393.5 kJ/ mol

ΔS =0.0029 kJ/mol K

T = 298 K

To solve:

Gibbs free energy (ΔG)

We know;

ΔG = ΔH - TΔS

ΔG  = -393.5 - (298 × 0.0029)

ΔG = -393.5 - 0.8642

ΔG = -394.36 J

Therefore the Gibbs free energy (ΔG) for the reaction is -394.36 J

thats a little if u want the answer just look it up on google thats what i do haha : )