N2(g) + 3H2(g) -> 2NH 3(g)

Calculate the mass in g of Ammonia (NH3) if you react 10.0g of hydrogen with excess nitrogen.

a.) 17.04 g

b.) 84.4 g

c.) 56.2 g

d.) 85.2 g

None of the options are correct. The correct answer is:

56.67g

Explanation:

N2 + 3H2 —> 2NH3

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

From the equation,

6g of H2 produced 34g of NH3.

Therefore, 10g of H2 will produce = (10 x 34)/6 = 56.67g of NH3

Therefore, 56.67g of NH3 are produced