See if you can balance the unbalanced reaction that appears on the screen for the combustion of methane:

CH4 + O2 > CO2 + H20

and for the partial combustion of methane:

CH4 + O2 > CO2 + CO + H20 + C

Notice that the partial combustion of methane is responsible for the production of an extremely dangerous gas. What gas is it and why is it so dangerous?

The answer to your question is below

Explanation:

a)

Unbalanced chemical reaction

                    CH₄  +  O₂  ⇒   CO₂   +   H₂O

            Reactants    Elements     Products

                    1                 C                   1

                   4                 H                   2

                   2                 O                   3

Balanced chemical reaction

                  CH₄  +  2O₂  ⇒   CO₂   +   2H₂O

            Reactants    Elements     Products

                    1                 C                   1

                   4                 H                   4

                   2                 O                   4

b)

Unbalanced chemical reaction

                  CH₄  +  O₂   ⇒   CO₂  +  CO  +  H₂O  +  C

            Reactants    Elements     Products

                    1                 C                   3

                   4                 H                   2

                   2                 O                   4                

Balanced chemical reaction

             6CH₄  +  9O₂   ⇒   2CO₂  +  2CO  +  12H₂O  + 2C

            Reactants    Elements     Products

                   6                 C                   6

                  24                 H                 24

                   18                O                   18

The partial combustion of Methane produces CO (carbon monoxide) is a highly poisonous, odorless, colorless and tasteless gas. When it combines with hemoglobin, hemoglobin becomes ineffective for delivering oxygen to tissues.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

a polar bond is formed when electrons are shared unevenly between atoms