What would be the oxidation and reduction half reactions for this equation?

MgCl2(aq) + Fe(s) ➝ FeCl2(aq) + Mg(s)

Fe(s) → Fe²⁺(aq) + 2e⁻   OXIDATION

Mg²⁺(aq) + 2e⁻ → Mg(s)   REDUCTION

Explanation:

The redox reaction is: MgCl₂(aq) + Fe(s) → FeCl₂(aq) + Mg(s)

We need to know that elements in ground state have 0 as the oxidation state.

Iron in the reactants, and Mg in the products

In the magnessium chloride, the Mg acts with+2, so the oxidation state has decreased → REDUCTION

In the iron(II) chloride, the Fe acts with +2, so the oxidation statehas increased → OXIDATION

The half reactions are:

Fe(s) → Fe²⁺(aq) + 2e⁻   OXIDATION

Mg²⁺(aq) + 2e⁻ → Mg(s)   REDUCTION

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

c

explanation: