Complete and balance the precipitation reactions. Include physical states in your equations.
1- AgNO3(aq)+NaCl(aq) <>2- K3PO4(aq)+MgCl2(aq) <>

AgNO₃(aq) + NaCl(aq) ⇄ AgCl(s)↓ +  NaNO₃(aq)                  Kps

2K₃PO₄(aq) + 3MgCl₂(aq) ⇄ 6KCl (aq) + Mg₃(PO₄)₂ (s)↓       Kps

Explanation:

In the first reaction (1) we have:

Silver nitrate and sodium chloride as the reactants. Then the products will be, silver chloride (s) and sodium nitrate.

We know that all the salts from the nitrate are soluble, so the chloride will react to the silver cation to make the precipitate, an insoluble salt.

AgNO₃(aq) + NaCl(aq)  ⇄  AgCl(s)↓ +  NaNO₃(aq)          Kps

For the second reaction (2), the reactants are:

Potassium phosphate and magnessium chloride

Phosphate salts are insoluble, except for the group 1. The same as chloride that makes soluble salts with the elements from the group 1.

The equation that makes the precipitate is.

2K₃PO₄(aq) + 3MgCl₂(aq) ⇄ 6KCl (aq) + Mg₃(PO₄)₂ (s)↓                  Kps

1) AgNO3(aq) + NaCl(aq) → NaNO3(aq) + AgCl(s)↓

2) 2K3PO4(aq) + 3MgCl2(aq) → Mg3(PO4)2(s)↓ + 6KCl(aq)

Explanation:

1) AgNO3(aq)+NaCl(aq) <>

Step 1: The unbalanced equation

AgNO3(aq)+NaCl(aq) → Ag+ + NO3- + Na+ + Cl-

Step 2: The balanced equation

AgNO3(aq) + NaCl(aq) → NaNO3(aq) + AgCl(s)↓

2) K3PO4(aq)+MgCl2(aq) <>

Step 1: The unbalanced equation

K3PO4(aq) + MgCl2(aq) → 3K+ + PO4^3- + Mg^2+ + 2Cl-

K3PO4(aq) + MgCl2(aq) → Mg3(PO4)2(s) + KCl(aq)

Step 2: The balanced equation

2K3PO4(aq) + 3MgCl2(aq) → Mg3(PO4)2(s)↓ + 6KCl(aq)

it means there are 3 atoms of oxygen