The amount of heat needed to raise 50 g of a substance by 20°C is 325 J. What is the specific heat of the substance? Use the equation C = q/mΔT.

The formula for calculating the specific heat of a substance(c) is:

c=q/mΔt;

Explanation:

Specific heat(c)=the amount of heat per unit mass required to raise the temperatueby one degree celsius is called specific heat.

c=q/mΔt;

where q=heat of substance

m=mass of substance

Δt=temperature of substance

Given;

heat of  substance(q)=325J

mass of substance(m)=50g=0.050kg

temperature(Δt)=20°C

To solve:

specific heat of a substance

we know,

c=q/mΔt

c=

c=2.218J/kgK

∴the specific heat of a substance(c) is 2.218J/kgK

explanation:

crosscutting concepts have application across all domains of science. as such, they are a way of linking the different domains of science. they include patterns; cause and effect; scale, proportion, and quantity; systems and system models; energy and matter; structure and function; and stability and change.

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.