A gas occupies 2.0 L at 353 Kelvin what temperature will it be if it occupies 0.85 L

T₂ = 150.03 K

Explanation:

Given data:

Initial volume of gas = 2.0 L

Initial temperature = 353 k

Final temperature = ?

Final volume = 0.85 L

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂  =  V₂ T₁ /V₁

T₂ = 0.85 L × 353 K / 2.0 L

T₂ = 300.05 L.K / 2.0 L

T₂ = 150.03 K

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

you need to stop taking that class