How many grams of CaCl2 will be required in order to make a 60mL solution with the strength of 4M? M= mol solute / L of solution

26.6 g of CaCl₂ are required to make a 4M solution

Explanation:

4 M = Molarity of the solution

This is a type of concentratrion for solutions, that indicates the moles of solute in 1L of solution.

Solution's volume = 60 mL

We need to convert the volume from mL to L → 60 mL . 1L / 1000mL = 0.060L

Molarity = mol / volume (L) → Molarity . volume (L) = mol

4 M . 0.060L = 0.24 mol of solute

Let's convert the moles to mass → Molar mass CaCl₂

0.24 mol . 110.98 g / 1mol = 26.6 g

sry but any answer choices

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g