If 30 g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the percent yield of the experiment?

Percent yield of NaCl = 20.85%

Explanation:

Given data:

Mass of HCl = 30 g

Actual yield of NaCl = 10 g

Percent yield of NaCl = ?

Solution:

Chemical equation:

HCl  + NaOH   →    NaCl  + H₂O

Moles of HCl:

Number of moles = mass/ molar mass

Number of moles = 30 g/ 36.5 g/mol

Number of moles = 0.82 mol

Now we will compare the moles of HCl with NaCl

                             HCl        :        NaCl

                                1          :            1

                              0.82      :        0.82

Theoretical yield:

Mass = number of moles × molar mass

Mass = 0.82 mol × 58.5 g/mol

Mass = 47.97 g

Percentage yield:

Formula:

Percent yield = Actual yield / theoretical yield × 100

Now we will put the values.

Percent yield = 10 g / 47.97 g × 100

Percent yield = 20.85%

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i think it is d. e because the next one is igneous.