If 30g of HCl is reacted with excess NaOH, and 10g of NaCl is produced, what is the percent yield of the experiment?

Percent yield = 20.85%

Explanation:

Given data:

Mass of HCl = 30 g

Mass of NaCl produced = 10 g

Percent yield of NaCl = ?

Solution:

Chemical equation:

HCl  + NaOH   →    NaCl  + H₂O

Number of moles of HCl:

Number of moles = mass/ molar mass

Number of moles = 30 g/ 36.5 g/mol

Number of moles = 0.82 mol

Now we will compare the moles of HCl with NaCl

                              HCl        :        NaCl

                                 1          :            1

                               0.82      :        0.82

Theoretical yield:

Mass of NaCl:

Mass = number of moles × molar mass

Mass = 0.82 mol × 58.5 g/mol

Mass = 47.97 g

Percent yield:

Percent yield = Actual yield / theoretical yield × 100

Percent yield = 10 g / 47.97 g × 100

Percent yield = 20.85%

the answer would be a