The equilibrium constant Kc for the reaction 2NO(g)+O2(g)⇌2NO2(g) is 6.9×105 at 500 K. A 5.0 L reaction vessel at 500 K was filled with 0.056 mol of NO, 1.0 mol of O2, and 0.90 mol of NO2. Part A What is the value of Qc?

Q = 1291.5

Explanation:

Step 1: Data given

Kc = 6.9 * 10^5 at 500 K

Volume = 5.0 L

Number of moles NO = 0.056 moles

Number of moles O2 = 1.0 moles

Number of moles NO2 = 0.90 moles

Step 2: The balanced equation

2NO(g) + O2(g) ⇌ 2NO2(g)

Step 3: Calculate the concentration

Concentration = moles / volume

[NO] = 0.056 moles / 5.0 L

[NO]= 0.0112 M

[O2] = 1.0 mol / 5.0L

[O2] = 0.2 M

[NO2] = 0.90 moles / 5.0L

[NO2] = 0.18 M

Step 4: Calculate Q

Q = [NO2]²/[NO]²[O2]

Q = [0.18²]/[(0.0112²)(0.2)]

Q = 1291.5

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