A solution is prepared by combining 100.0 mL of 0.20 MNa2SO4with 100.0 mL of0.50 MK2SO4. Which of the following choices has correctly arranged the ions in thissolution in order of increasing concentration?lowest highest concentration concentration (A) SO42–Na+K+(B) Na+SO42–K+(C) Na+K+SO42–(D) K+Na+SO42–2.A solution was prepared by dissolving 11 grams of anhydrous calcium chloride (F. W. = 110.98)into water so that the total volume is 500. mL. What is the concentration of chloride ions inthis solution?3.How many grams of glucose (F. W. = 180.156) are present in 500. mL of a 0.50 Mglucosesolution? Subscribe to Course Hero to unlock this document Subscribe to Course Hero to unlock this document

the answer is either b or c

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

m=9

step-by-step explanation:

did anyone actually do this? like if anyone has submitted this i rly need .