Use the table to calculate ΔH°rnx for the following reaction

The answer to your question is ΔH° rxn = -1343.9 kJ/mol

Explanation:

                       P₄O₆ (s)  +  2 O₂ (g)   ⇒  P₄O₁₀

ΔH°rxn = ?

Formula

ΔH°rxn = ∑H° products - ∑H° reactants

H° P₄O₆ = -1640.1 kJ/mol

H° O₂ = 0 kJ/mol

H° P₄O₁₀ = -2984 kJ/mol

-Substitution

ΔH° rxn = (-2984) - (-1640.1) - (0)

-Simplification

ΔH° rxn = -2984 + 1640.1

ΔH° rxn = -1343.9 kJ/mol

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