Sodium vapor lamps are used to illuminate streets and highways. The very bright light emitted by these lamps is actually due to two closely spaced emission lines in the visible region of the electromagnetic spectrum. One of these lines has a wavelength of 5.890 X 10⁻⁷ m, and the other line has a wavelength of 5.896 X 10⁻⁷ m. A) What are the wavelengths of these radiations in centimeters? B) Calculate the frequencies of these radiations. Show work please

Wavelengths of these radiations in centimeters

5.890 x 10⁻⁵ cm & 5.896 x 10⁻⁵ cm

Frequencies of these radiations

0.509 x 10¹⁵ sec⁻¹ & 0.508 x 10¹⁵ sec⁻¹

Explanation:

Part A

We know

                              1 m = 100 cm

so,          5.89 x 10⁻⁷ m   =   5.89 x 10⁻⁵ cm

Similarly 5.896 x 10⁻⁷ m = 5.896 x 10⁻⁵ cm

Part B

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.