What volume is occupied by 1.892 mol of O2 at 310.5 K and 121.3 kPa?

The volume occupied is 40, 14 L

Explanation:

We use the formula PV=nRT. We convert the unit of pressure in kPa into atm.

101,325kPa1atm

121,3kPax=(121,3kPax 1 atm)/101,325kPa=1, 2 atm

PV=nRT>V=(nRT)/P

V=(1,892 mol x 0,082 l atm/K mol x 310,5K)/1, 2 atm= 40,14 L

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.