When 22 grams of water undergoes a temeprature change from 35 ˚C to 65 ˚C, how much energy does the water absorb? The specific heat of water is 4.184.

2761.44 joules

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since,

Q = ?

Mass of oil = 22g

C = 4.184Jg°C

Φ = (Final temperature - Initial temperature)

= 65°C - 35°C = 30°C

Then, Q = MCΦ

Q = 22g x 4.184Jg°C x 30°C

Q = 2761.41 Joules

Thus, water absorb 2761.44 joules of heat.

i just learnt this recently but i need to look through my notes again

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.